LEETCODEEasy
Isomorphic Strings
Given two strings s and t, determine if they are isomorphic.
Two strings s and t are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character, but a character may map to itself.
Example 1:
Input: s = "egg", t = "add"
Output: true
Explanation:
The strings s and t can be made identical by:
- Mapping
'e'to'a'. - Mapping
'g'to'd'.
Example 2:
Input: s = "f11", t = "b23"
Output: false
Explanation:
The strings s and t can not be made identical as '1' needs to be mapped to both '2' and '3'.
Example 3:
Input: s = "paper", t = "title"
Output: true
Constraints:
1 <= s.length <= 5 * 104t.length == s.lengthsandtconsist of any valid ascii character.
풀이 TypeScript
function morphString(input: string): string {
const map: Record<string, number> = {};
let lastIndex = 0;
return input.split('')
.map((char) => {
if (!(char in map)) {
map[char] = ++lastIndex;
}
return map[char];
}).join('');
}
function isIsomorphic(s: string, t: string): boolean {
return morphString(s) === morphString(t);
}복사됨